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0.25(3x+1)=1/6(5-2x)
We move all terms to the left:
0.25(3x+1)-(1/6(5-2x))=0
Domain of the equation: 6(5-2x))!=0We add all the numbers together, and all the variables
x∈R
0.25(3x+1)-(1/6(-2x+5))=0
We multiply parentheses
0.75x-(1/6(-2x+5))+0.25=0
We multiply all the terms by the denominator
(0.75x)*6(-2x+5))-(1+(0.25)*6(-2x+5))=0
We add all the numbers together, and all the variables
(+0.75x)*6(-2x+5))-(1+(0.25)*6(-2x+5))=0
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