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6+1/2b=5/6b
We move all terms to the left:
6+1/2b-(5/6b)=0
Domain of the equation: 2b!=0
b!=0/2
b!=0
b∈R
Domain of the equation: 6b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
1/2b-(+5/6b)+6=0
We get rid of parentheses
1/2b-5/6b+6=0
We calculate fractions
6b/12b^2+(-10b)/12b^2+6=0
We multiply all the terms by the denominator
6b+(-10b)+6*12b^2=0
Wy multiply elements
72b^2+6b+(-10b)=0
We get rid of parentheses
72b^2+6b-10b=0
We add all the numbers together, and all the variables
72b^2-4b=0
a = 72; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·72·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*72}=\frac{0}{144} =0 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*72}=\frac{8}{144} =1/18 $
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