6+1/2(8z-3)=2z+5+2z

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Solution for 6+1/2(8z-3)=2z+5+2z equation: 



6+1/2(8z-3)=2z+5+2z

We move all terms to the left:

6+1/2(8z-3)-(2z+5+2z)=0



Domain of the equation: 2(8z-3)!=0

z∈R



We add all the numbers together, and all the variables

1/2(8z-3)-(4z+5)+6=0

We get rid of parentheses

1/2(8z-3)-4z-5+6=0

We multiply all the terms by the denominator


-4z*2(8z-3)-5*2(8z-3)+6*2(8z-3)+1=0

Wy multiply elements

-8z^2(8-10z(8+12z(8+1=0

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