1/6(6x+12)=-1/5(20x-15)

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Solution for 1/6(6x+12)=-1/5(20x-15) equation: 



1/6(6x+12)=-1/5(20x-15)

We move all terms to the left:

1/6(6x+12)-(-1/5(20x-15))=0



Domain of the equation: 6(6x+12)!=0

x∈R





Domain of the equation: 5(20x-15))!=0

x∈R



We calculate fractions


(5x2/(6(6x+12)*5(20x-15)))+(-(-6x6)/(6(6x+12)*5(20x-15)))=0



We calculate terms in parentheses: +(5x2/(6(6x+12)*5(20x-15))), so:

5x2/(6(6x+12)*5(20x-15))

We multiply all the terms by the denominator


5x2

We add all the numbers together, and all the variables

5x^2

Back to the equation:

+(5x^2)





We calculate terms in parentheses: +(-(-6x6)/(6(6x+12)*5(20x-15))), so:

-(-6x6)/(6(6x+12)*5(20x-15))

We add all the numbers together, and all the variables

-(-6x^6)/(6(6x+12)*5(20x-15))

We multiply all the terms by the denominator


-(-6x^6)

We do not support expression: x^6

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