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6+(5x-3)=9-(3x-5)
We move all terms to the left:
6+(5x-3)-(9-(3x-5))=0
We get rid of parentheses
5x-(9-(3x-5))-3+6=0
We calculate terms in parentheses: -(9-(3x-5)), so:We add all the numbers together, and all the variables
9-(3x-5)
determiningTheFunctionDomain -(3x-5)+9
We get rid of parentheses
-3x+5+9
We add all the numbers together, and all the variables
-3x+14
Back to the equation:
-(-3x+14)
5x-(-3x+14)+3=0
We get rid of parentheses
5x+3x-14+3=0
We add all the numbers together, and all the variables
8x-11=0
We move all terms containing x to the left, all other terms to the right
8x=11
x=11/8
x=1+3/8
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