3x+(4x-2)=10x+(3x-9)

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Solution for 3x+(4x-2)=10x+(3x-9) equation: 



3x+(4x-2)=10x+(3x-9)

We move all terms to the left:

3x+(4x-2)-(10x+(3x-9))=0

We get rid of parentheses

3x+4x-(10x+(3x-9))-2=0



We calculate terms in parentheses: -(10x+(3x-9)), so:

10x+(3x-9)

We get rid of parentheses

10x+3x-9

We add all the numbers together, and all the variables

13x-9

Back to the equation:

-(13x-9)



We add all the numbers together, and all the variables

7x-(13x-9)-2=0

We get rid of parentheses

7x-13x+9-2=0

We add all the numbers together, and all the variables

-6x+7=0

We move all terms containing x to the left, all other terms to the right

-6x=-7

x=-7/-6

x=1+1/6

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