6+(4-m)=8(3m+5)

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Solution for 6+(4-m)=8(3m+5) equation: 



6+(4-m)=8(3m+5)

We move all terms to the left:

6+(4-m)-(8(3m+5))=0

We add all the numbers together, and all the variables

(-1m+4)-(8(3m+5))+6=0

We get rid of parentheses

-1m-(8(3m+5))+4+6=0



We calculate terms in parentheses: -(8(3m+5)), so:

8(3m+5)

We multiply parentheses

24m+40

Back to the equation:

-(24m+40)



We add all the numbers together, and all the variables

-1m-(24m+40)+10=0

We get rid of parentheses

-1m-24m-40+10=0

We add all the numbers together, and all the variables

-25m-30=0

We move all terms containing m to the left, all other terms to the right

-25m=30

m=30/-25

m=-1+1/5

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