3x-8-(4+2x)=6(2x+1)+11

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Solution for 3x-8-(4+2x)=6(2x+1)+11 equation: 



3x-8-(4+2x)=6(2x+1)+11

We move all terms to the left:

3x-8-(4+2x)-(6(2x+1)+11)=0

We add all the numbers together, and all the variables

3x-(2x+4)-(6(2x+1)+11)-8=0

We get rid of parentheses

3x-2x-(6(2x+1)+11)-4-8=0



We calculate terms in parentheses: -(6(2x+1)+11), so:

6(2x+1)+11

We multiply parentheses

12x+6+11

We add all the numbers together, and all the variables

12x+17

Back to the equation:

-(12x+17)



We add all the numbers together, and all the variables

x-(12x+17)-12=0

We get rid of parentheses

x-12x-17-12=0

We add all the numbers together, and all the variables

-11x-29=0

We move all terms containing x to the left, all other terms to the right

-11x=29

x=29/-11

x=-2+7/11

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