6*(y+3)=18-(2-4y)

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Solution for 6*(y+3)=18-(2-4y) equation: 



6(y+3)=18-(2-4y)

We move all terms to the left:

6(y+3)-(18-(2-4y))=0

We add all the numbers together, and all the variables

6(y+3)-(18-(-4y+2))=0

We multiply parentheses

6y-(18-(-4y+2))+18=0



We calculate terms in parentheses: -(18-(-4y+2)), so:

18-(-4y+2)

determiningTheFunctionDomain
-(-4y+2)+18

We get rid of parentheses

4y-2+18

We add all the numbers together, and all the variables

4y+16

Back to the equation:

-(4y+16)



We get rid of parentheses

6y-4y-16+18=0

We add all the numbers together, and all the variables

2y+2=0

We move all terms containing y to the left, all other terms to the right

2y=-2

y=-2/2

y=-1

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