6*(3b+5)=2*(6b-21)

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Solution for 6*(3b+5)=2*(6b-21) equation:



6(3b+5)=2(6b-21)
We move all terms to the left:
6(3b+5)-(2(6b-21))=0
We multiply parentheses
18b-(2(6b-21))+30=0
We calculate terms in parentheses: -(2(6b-21)), so:
2(6b-21)
We multiply parentheses
12b-42
Back to the equation:
-(12b-42)
We get rid of parentheses
18b-12b+42+30=0
We add all the numbers together, and all the variables
6b+72=0
We move all terms containing b to the left, all other terms to the right
6b=-72
b=-72/6
b=-12

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