5-(2-x)+3=10-4(1+x)=

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Solution for 5-(2-x)+3=10-4(1+x)= equation: 



5-(2-x)+3=10-4(1+x)=

We move all terms to the left:

5-(2-x)+3-(10-4(1+x))=0

We add all the numbers together, and all the variables

-(-1x+2)-(10-4(x+1))+5+3=0

We add all the numbers together, and all the variables

-(-1x+2)-(10-4(x+1))+8=0

We get rid of parentheses

1x-(10-4(x+1))-2+8=0



We calculate terms in parentheses: -(10-4(x+1)), so:

10-4(x+1)

determiningTheFunctionDomain
-4(x+1)+10

We multiply parentheses

-4x-4+10

We add all the numbers together, and all the variables

-4x+6

Back to the equation:

-(-4x+6)



We add all the numbers together, and all the variables

x-(-4x+6)+6=0

We get rid of parentheses

x+4x-6+6=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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