6(z-5)=12

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Solution for 6(z-5)=12 equation: 



6(z-5)=12

We move all terms to the left:

6(z-5)-(12)=0

We multiply parentheses

6z-30-12=0

We add all the numbers together, and all the variables

6z-42=0

We move all terms containing z to the left, all other terms to the right

6z=42

z=42/6

z=7

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