-2(2t-5)=3(t+1)

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Solution for -2(2t-5)=3(t+1) equation: 



-2(2t-5)=3(t+1)

We move all terms to the left:

-2(2t-5)-(3(t+1))=0

We multiply parentheses

-4t-(3(t+1))+10=0



We calculate terms in parentheses: -(3(t+1)), so:

3(t+1)

We multiply parentheses

3t+3

Back to the equation:

-(3t+3)



We get rid of parentheses

-4t-3t-3+10=0

We add all the numbers together, and all the variables

-7t+7=0

We move all terms containing t to the left, all other terms to the right

-7t=-7

t=-7/-7

t=1

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