6(z-2)=8z-1

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Solution for 6(z-2)=8z-1 equation: 



6(z-2)=8z-1

We move all terms to the left:

6(z-2)-(8z-1)=0

We multiply parentheses

6z-(8z-1)-12=0

We get rid of parentheses

6z-8z+1-12=0

We add all the numbers together, and all the variables

-2z-11=0

We move all terms containing z to the left, all other terms to the right

-2z=11

z=11/-2

z=-5+1/2

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