6(z-2)=33-32

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Solution for 6(z-2)=33-32 equation:



6(z-2)=33-32
We move all terms to the left:
6(z-2)-(33-32)=0
We add all the numbers together, and all the variables
6(z-2)-1=0
We multiply parentheses
6z-12-1=0
We add all the numbers together, and all the variables
6z-13=0
We move all terms containing z to the left, all other terms to the right
6z=13
z=13/6
z=2+1/6

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