13(s+2)=4(s-12)+2

Solution for 13(s+2)=4(s-12)+2 equation:

13(s+2)=4(s-12)+2

We move all terms to the left:

13(s+2)-(4(s-12)+2)=0

We multiply parentheses

13s-(4(s-12)+2)+26=0


We calculate terms in parentheses: -(4(s-12)+2), so:

4(s-12)+2

We multiply parentheses

4s-48+2

We add all the numbers together, and all the variables

4s-46

Back to the equation:

-(4s-46)


We get rid of parentheses

13s-4s+46+26=0

We add all the numbers together, and all the variables

9s+72=0

We move all terms containing s to the left, all other terms to the right

9s=-72

s=-72/9

s=-8