6(z-2)+4=4(8-z)

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Solution for 6(z-2)+4=4(8-z) equation: 



6(z-2)+4=4(8-z)

We move all terms to the left:

6(z-2)+4-(4(8-z))=0

We add all the numbers together, and all the variables

6(z-2)-(4(-1z+8))+4=0

We multiply parentheses

6z-(4(-1z+8))-12+4=0



We calculate terms in parentheses: -(4(-1z+8)), so:

4(-1z+8)

We multiply parentheses

-4z+32

Back to the equation:

-(-4z+32)



We add all the numbers together, and all the variables

6z-(-4z+32)-8=0

We get rid of parentheses

6z+4z-32-8=0

We add all the numbers together, and all the variables

10z-40=0

We move all terms containing z to the left, all other terms to the right

10z=40

z=40/10

z=4

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