3x-33=2(1+5x)

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Solution for 3x-33=2(1+5x) equation: 



3x-33=2(1+5x)

We move all terms to the left:

3x-33-(2(1+5x))=0

We add all the numbers together, and all the variables

3x-(2(5x+1))-33=0



We calculate terms in parentheses: -(2(5x+1)), so:

2(5x+1)

We multiply parentheses

10x+2

Back to the equation:

-(10x+2)



We get rid of parentheses

3x-10x-2-33=0

We add all the numbers together, and all the variables

-7x-35=0

We move all terms containing x to the left, all other terms to the right

-7x=35

x=35/-7

x=-5

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