6(z+1)=3(3z+1)

Solution for 6(z+1)=3(3z+1) equation:

Simplifying
6(z + 1) = 3(3z + 1)

Reorder the terms:
6(1 + z) = 3(3z + 1)
(1 * 6 + z * 6) = 3(3z + 1)
(6 + 6z) = 3(3z + 1)

Reorder the terms:
6 + 6z = 3(1 + 3z)
6 + 6z = (1 * 3 + 3z * 3)
6 + 6z = (3 + 9z)

Solving
6 + 6z = 3 + 9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9z' to each side of the equation.
6 + 6z + -9z = 3 + 9z + -9z

Combine like terms: 6z + -9z = -3z
6 + -3z = 3 + 9z + -9z

Combine like terms: 9z + -9z = 0
6 + -3z = 3 + 0
6 + -3z = 3

Add '-6' to each side of the equation.
6 + -6 + -3z = 3 + -6

Combine like terms: 6 + -6 = 0
0 + -3z = 3 + -6
-3z = 3 + -6

Combine like terms: 3 + -6 = -3
-3z = -3

Divide each side by '-3'.
z = 1

Simplifying
z = 1