6(y-72)=2y+92

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Solution for 6(y-72)=2y+92 equation: 



6(y-72)=2y+92

We move all terms to the left:

6(y-72)-(2y+92)=0

We multiply parentheses

6y-(2y+92)-432=0

We get rid of parentheses

6y-2y-92-432=0

We add all the numbers together, and all the variables

4y-524=0

We move all terms containing y to the left, all other terms to the right

4y=524

y=524/4

y=131

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