18(x-2)=3(6x-5)-21

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Solution for 18(x-2)=3(6x-5)-21 equation: 



18(x-2)=3(6x-5)-21

We move all terms to the left:

18(x-2)-(3(6x-5)-21)=0

We multiply parentheses

18x-(3(6x-5)-21)-36=0



We calculate terms in parentheses: -(3(6x-5)-21), so:

3(6x-5)-21

We multiply parentheses

18x-15-21

We add all the numbers together, and all the variables

18x-36

Back to the equation:

-(18x-36)



We get rid of parentheses

18x-18x+36-36=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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