7x-5(2x-4)-8=15-(3-x)-4x

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Solution for 7x-5(2x-4)-8=15-(3-x)-4x equation: 



7x-5(2x-4)-8=15-(3-x)-4x

We move all terms to the left:

7x-5(2x-4)-8-(15-(3-x)-4x)=0

We add all the numbers together, and all the variables

7x-5(2x-4)-(15-(-1x+3)-4x)-8=0

We multiply parentheses

7x-10x-(15-(-1x+3)-4x)+20-8=0



We calculate terms in parentheses: -(15-(-1x+3)-4x), so:

15-(-1x+3)-4x

determiningTheFunctionDomain
-(-1x+3)-4x+15

We add all the numbers together, and all the variables

-4x-(-1x+3)+15

We get rid of parentheses

-4x+1x-3+15

We add all the numbers together, and all the variables

-3x+12

Back to the equation:

-(-3x+12)



We add all the numbers together, and all the variables

-3x-(-3x+12)+12=0

We get rid of parentheses

-3x+3x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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