6(y-5)+4y=(y+2)

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Solution for 6(y-5)+4y=(y+2) equation: 



6(y-5)+4y=(y+2)

We move all terms to the left:

6(y-5)+4y-((y+2))=0

We add all the numbers together, and all the variables

4y+6(y-5)-((y+2))=0

We multiply parentheses

4y+6y-((y+2))-30=0



We calculate terms in parentheses: -((y+2)), so:

(y+2)

We get rid of parentheses

y+2

Back to the equation:

-(y+2)



We add all the numbers together, and all the variables

10y-(y+2)-30=0

We get rid of parentheses

10y-y-2-30=0

We add all the numbers together, and all the variables

9y-32=0

We move all terms containing y to the left, all other terms to the right

9y=32

y=32/9

y=3+5/9

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