31=5(m+4)+7(m-7)

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Solution for 31=5(m+4)+7(m-7) equation: 



31=5(m+4)+7(m-7)

We move all terms to the left:

31-(5(m+4)+7(m-7))=0



We calculate terms in parentheses: -(5(m+4)+7(m-7)), so:

5(m+4)+7(m-7)

We multiply parentheses

5m+7m+20-49

We add all the numbers together, and all the variables

12m-29

Back to the equation:

-(12m-29)



We get rid of parentheses

-12m+29+31=0

We add all the numbers together, and all the variables

-12m+60=0

We move all terms containing m to the left, all other terms to the right

-12m=-60

m=-60/-12

m=+5

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