6(y-4)=2y-40

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Solution for 6(y-4)=2y-40 equation: 



6(y-4)=2y-40

We move all terms to the left:

6(y-4)-(2y-40)=0

We multiply parentheses

6y-(2y-40)-24=0

We get rid of parentheses

6y-2y+40-24=0

We add all the numbers together, and all the variables

4y+16=0

We move all terms containing y to the left, all other terms to the right

4y=-16

y=-16/4

y=-4

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