6(y-4)-3(5y+1)=4(y-2)-4(2(y+1)

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Solution for 6(y-4)-3(5y+1)=4(y-2)-4(2(y+1) equation: 



6(y-4)-3(5y+1)=4(y-2)-4(2(y+1)

We move all terms to the left:

6(y-4)-3(5y+1)-(4(y-2)-4(2(y+1))=0

We multiply parentheses

6y-15y-(4(y-2)-4(2(y+1))-24-3=0

We add all the numbers together, and all the variables

-9y-(4(y-2)-4(2(y+1))-24-3=0

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