-2(n-2)=-3n-3(1+2n)

Solution for -2(n-2)=-3n-3(1+2n) equation:

-2(n-2)=-3n-3(1+2n)

We move all terms to the left:

-2(n-2)-(-3n-3(1+2n))=0

We add all the numbers together, and all the variables

-2(n-2)-(-3n-3(2n+1))=0

We multiply parentheses

-2n-(-3n-3(2n+1))+4=0


We calculate terms in parentheses: -(-3n-3(2n+1)), so:

-3n-3(2n+1)

We multiply parentheses

-3n-6n-3

We add all the numbers together, and all the variables

-9n-3

Back to the equation:

-(-9n-3)


We get rid of parentheses

-2n+9n+3+4=0

We add all the numbers together, and all the variables

7n+7=0

We move all terms containing n to the left, all other terms to the right

7n=-7

n=-7/7

n=-1