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6(y-2)=3(y-1)
We move all terms to the left:
6(y-2)-(3(y-1))=0
We multiply parentheses
6y-(3(y-1))-12=0
We calculate terms in parentheses: -(3(y-1)), so:We get rid of parentheses
3(y-1)
We multiply parentheses
3y-3
Back to the equation:
-(3y-3)
6y-3y+3-12=0
We add all the numbers together, and all the variables
3y-9=0
We move all terms containing y to the left, all other terms to the right
3y=9
y=9/3
y=3
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