6(y-11)+9=1/3(27+3y)-16

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Solution for 6(y-11)+9=1/3(27+3y)-16 equation: 



6(y-11)+9=1/3(27+3y)-16

We move all terms to the left:

6(y-11)+9-(1/3(27+3y)-16)=0



Domain of the equation: 3(27+3y)-16)!=0

y∈R



We add all the numbers together, and all the variables

6(y-11)-(1/3(3y+27)-16)+9=0

We multiply parentheses

6y-(1/3(3y+27)-16)-66+9=0

We multiply all the terms by the denominator


6y*3(3y+27)-66*3(3y+27)-16)+9*3(3y-16)-(1+27)-16)=0

We add all the numbers together, and all the variables

6y*3(3y+27)-66*3(3y+27)-16)+9*3(3y-16)-28-16)=0

We add all the numbers together, and all the variables

6y*3(3y+27)-66*3(3y+27)-16)+9*3(3y=0

Wy multiply elements

18y^2(3-198y(3-16)+9*3(3y=0

We add all the numbers together, and all the variables

18y^2(3-198y(-13)+9*3(3y=0

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