4(3x-2)=-2(x-5)-4

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Solution for 4(3x-2)=-2(x-5)-4 equation: 



4(3x-2)=-2(x-5)-4

We move all terms to the left:

4(3x-2)-(-2(x-5)-4)=0

We multiply parentheses

12x-(-2(x-5)-4)-8=0



We calculate terms in parentheses: -(-2(x-5)-4), so:

-2(x-5)-4

We multiply parentheses

-2x+10-4

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We get rid of parentheses

12x+2x-6-8=0

We add all the numbers together, and all the variables

14x-14=0

We move all terms containing x to the left, all other terms to the right

14x=14

x=14/14

x=1

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