6(y+4)=10(y-2)

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Solution for 6(y+4)=10(y-2) equation: 



6(y+4)=10(y-2)

We move all terms to the left:

6(y+4)-(10(y-2))=0

We multiply parentheses

6y-(10(y-2))+24=0



We calculate terms in parentheses: -(10(y-2)), so:

10(y-2)

We multiply parentheses

10y-20

Back to the equation:

-(10y-20)



We get rid of parentheses

6y-10y+20+24=0

We add all the numbers together, and all the variables

-4y+44=0

We move all terms containing y to the left, all other terms to the right

-4y=-44

y=-44/-4

y=+11

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