3k+6+k=2(2k+3)

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Solution for 3k+6+k=2(2k+3) equation:



3k+6+k=2(2k+3)
We move all terms to the left:
3k+6+k-(2(2k+3))=0
We add all the numbers together, and all the variables
4k-(2(2k+3))+6=0
We calculate terms in parentheses: -(2(2k+3)), so:
2(2k+3)
We multiply parentheses
4k+6
Back to the equation:
-(4k+6)
We get rid of parentheses
4k-4k-6+6=0
We add all the numbers together, and all the variables
=0
k=0/1
k=0

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