6(y+3)=22-2(2-3y)

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Solution for 6(y+3)=22-2(2-3y) equation: 



6(y+3)=22-2(2-3y)

We move all terms to the left:

6(y+3)-(22-2(2-3y))=0

We add all the numbers together, and all the variables

6(y+3)-(22-2(-3y+2))=0

We multiply parentheses

6y-(22-2(-3y+2))+18=0



We calculate terms in parentheses: -(22-2(-3y+2)), so:

22-2(-3y+2)

determiningTheFunctionDomain
-2(-3y+2)+22

We multiply parentheses

6y-4+22

We add all the numbers together, and all the variables

6y+18

Back to the equation:

-(6y+18)



We get rid of parentheses

6y-6y-18+18=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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