5(4y+3)=15

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Solution for 5(4y+3)=15 equation: 



5(4y+3)=15

We move all terms to the left:

5(4y+3)-(15)=0

We multiply parentheses

20y+15-15=0

We add all the numbers together, and all the variables

20y=0

y=0/20

y=0

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