6(y+3)=-2(4y-1)+8y

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Solution for 6(y+3)=-2(4y-1)+8y equation: 



6(y+3)=-2(4y-1)+8y

We move all terms to the left:

6(y+3)-(-2(4y-1)+8y)=0

We multiply parentheses

6y-(-2(4y-1)+8y)+18=0



We calculate terms in parentheses: -(-2(4y-1)+8y), so:

-2(4y-1)+8y

We add all the numbers together, and all the variables

8y-2(4y-1)

We multiply parentheses

8y-8y+2

We add all the numbers together, and all the variables

2

Back to the equation:

-(2)



We add all the numbers together, and all the variables

6y+16=0

We move all terms containing y to the left, all other terms to the right

6y=-16

y=-16/6

y=-2+2/3

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