-2(u+2)=4u-7+3(3u+2)

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Solution for -2(u+2)=4u-7+3(3u+2) equation: 



-2(u+2)=4u-7+3(3u+2)

We move all terms to the left:

-2(u+2)-(4u-7+3(3u+2))=0

We multiply parentheses

-2u-(4u-7+3(3u+2))-4=0



We calculate terms in parentheses: -(4u-7+3(3u+2)), so:

4u-7+3(3u+2)

determiningTheFunctionDomain
4u+3(3u+2)-7

We multiply parentheses

4u+9u+6-7

We add all the numbers together, and all the variables

13u-1

Back to the equation:

-(13u-1)



We get rid of parentheses

-2u-13u+1-4=0

We add all the numbers together, and all the variables

-15u-3=0

We move all terms containing u to the left, all other terms to the right

-15u=3

u=3/-15

u=-1/5

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