6(y+3)+2=3(y+2)+20

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Solution for 6(y+3)+2=3(y+2)+20 equation: 



6(y+3)+2=3(y+2)+20

We move all terms to the left:

6(y+3)+2-(3(y+2)+20)=0

We multiply parentheses

6y-(3(y+2)+20)+18+2=0



We calculate terms in parentheses: -(3(y+2)+20), so:

3(y+2)+20

We multiply parentheses

3y+6+20

We add all the numbers together, and all the variables

3y+26

Back to the equation:

-(3y+26)



We add all the numbers together, and all the variables

6y-(3y+26)+20=0

We get rid of parentheses

6y-3y-26+20=0

We add all the numbers together, and all the variables

3y-6=0

We move all terms containing y to the left, all other terms to the right

3y=6

y=6/3

y=2

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