3/5(x-7)=7/10(x+2)

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Solution for 3/5(x-7)=7/10(x+2) equation: 



3/5(x-7)=7/10(x+2)

We move all terms to the left:

3/5(x-7)-(7/10(x+2))=0



Domain of the equation: 5(x-7)!=0

x∈R





Domain of the equation: 10(x+2))!=0

x∈R



We calculate fractions


(30xx/(5(x-7)*10(x+2)))+(-35xx/(5(x-7)*10(x+2)))=0



We calculate terms in parentheses: +(30xx/(5(x-7)*10(x+2))), so:

30xx/(5(x-7)*10(x+2))

We multiply all the terms by the denominator


30xx

Back to the equation:

+(30xx)





We calculate terms in parentheses: +(-35xx/(5(x-7)*10(x+2))), so:

-35xx/(5(x-7)*10(x+2))

We multiply all the terms by the denominator


-35xx

Back to the equation:

+(-35xx)



We get rid of parentheses

30xx-35xx=0

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