6(y+2)=2y+22

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Solution for 6(y+2)=2y+22 equation: 



6(y+2)=2y+22

We move all terms to the left:

6(y+2)-(2y+22)=0

We multiply parentheses

6y-(2y+22)+12=0

We get rid of parentheses

6y-2y-22+12=0

We add all the numbers together, and all the variables

4y-10=0

We move all terms containing y to the left, all other terms to the right

4y=10

y=10/4

y=2+1/2

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