6(y+2)-2(y-1)=6

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Solution for 6(y+2)-2(y-1)=6 equation: 



6(y+2)-2(y-1)=6

We move all terms to the left:

6(y+2)-2(y-1)-(6)=0

We multiply parentheses

6y-2y+12+2-6=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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