12-2(2w+1)=4w-2(4+w

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Solution for 12-2(2w+1)=4w-2(4+w equation: 



12-2(2w+1)=4w-2(4+w

We move all terms to the left:

12-2(2w+1)-(4w-2(4+w)=0

We add all the numbers together, and all the variables

-2(2w+1)-(4w-2(w+4)+12=0

We multiply parentheses

-4w-(4w-2(w+4)+12-2=0

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