40=5(-a-2)

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Solution for 40=5(-a-2) equation: 



40=5(-a-2)

We move all terms to the left:

40-(5(-a-2))=0

We add all the numbers together, and all the variables

-(5(-1a-2))+40=0



We calculate terms in parentheses: -(5(-1a-2)), so:

5(-1a-2)

We multiply parentheses

-5a-10

Back to the equation:

-(-5a-10)



We get rid of parentheses

5a+10+40=0

We add all the numbers together, and all the variables

5a+50=0

We move all terms containing a to the left, all other terms to the right

5a=-50

a=-50/5

a=-10

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