6(x/3+2)-4(7-x/4)=3x-16

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Solution for 6(x/3+2)-4(7-x/4)=3x-16 equation: 



6(x/3+2)-4(7-x/4)=3x-16

We move all terms to the left:

6(x/3+2)-4(7-x/4)-(3x-16)=0

We add all the numbers together, and all the variables

6(x/3+2)-4(-x/4+7)-(3x-16)=0

We multiply parentheses

6x+4x-(3x-16)+12-28=0

We get rid of parentheses

6x+4x-3x+16+12-28=0

We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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