6(x-8)-20=11(2x-3)+3x

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Solution for 6(x-8)-20=11(2x-3)+3x equation: 



6(x-8)-20=11(2x-3)+3x

We move all terms to the left:

6(x-8)-20-(11(2x-3)+3x)=0

We multiply parentheses

6x-(11(2x-3)+3x)-48-20=0



We calculate terms in parentheses: -(11(2x-3)+3x), so:

11(2x-3)+3x

We add all the numbers together, and all the variables

3x+11(2x-3)

We multiply parentheses

3x+22x-33

We add all the numbers together, and all the variables

25x-33

Back to the equation:

-(25x-33)



We add all the numbers together, and all the variables

6x-(25x-33)-68=0

We get rid of parentheses

6x-25x+33-68=0

We add all the numbers together, and all the variables

-19x-35=0

We move all terms containing x to the left, all other terms to the right

-19x=35

x=35/-19

x=-1+16/19

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