3(x-2)+5x+7=7x-2(x+4)

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Solution for 3(x-2)+5x+7=7x-2(x+4) equation: 



3(x-2)+5x+7=7x-2(x+4)

We move all terms to the left:

3(x-2)+5x+7-(7x-2(x+4))=0

We add all the numbers together, and all the variables

5x+3(x-2)-(7x-2(x+4))+7=0

We multiply parentheses

5x+3x-(7x-2(x+4))-6+7=0



We calculate terms in parentheses: -(7x-2(x+4)), so:

7x-2(x+4)

We multiply parentheses

7x-2x-8

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We add all the numbers together, and all the variables

8x-(5x-8)+1=0

We get rid of parentheses

8x-5x+8+1=0

We add all the numbers together, and all the variables

3x+9=0

We move all terms containing x to the left, all other terms to the right

3x=-9

x=-9/3

x=-3

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