6(x-8)+20=4(x+5)

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Solution for 6(x-8)+20=4(x+5) equation: 



6(x-8)+20=4(x+5)

We move all terms to the left:

6(x-8)+20-(4(x+5))=0

We multiply parentheses

6x-(4(x+5))-48+20=0



We calculate terms in parentheses: -(4(x+5)), so:

4(x+5)

We multiply parentheses

4x+20

Back to the equation:

-(4x+20)



We add all the numbers together, and all the variables

6x-(4x+20)-28=0

We get rid of parentheses

6x-4x-20-28=0

We add all the numbers together, and all the variables

2x-48=0

We move all terms containing x to the left, all other terms to the right

2x=48

x=48/2

x=24

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