6(x-6)=2(2x+1)+4x-19

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Solution for 6(x-6)=2(2x+1)+4x-19 equation:



6(x-6)=2(2x+1)+4x-19
We move all terms to the left:
6(x-6)-(2(2x+1)+4x-19)=0
We multiply parentheses
6x-(2(2x+1)+4x-19)-36=0
We calculate terms in parentheses: -(2(2x+1)+4x-19), so:
2(2x+1)+4x-19
We add all the numbers together, and all the variables
4x+2(2x+1)-19
We multiply parentheses
4x+4x+2-19
We add all the numbers together, and all the variables
8x-17
Back to the equation:
-(8x-17)
We get rid of parentheses
6x-8x+17-36=0
We add all the numbers together, and all the variables
-2x-19=0
We move all terms containing x to the left, all other terms to the right
-2x=19
x=19/-2
x=-9+1/2

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