16=2(u+3)-7

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Solution for 16=2(u+3)-7 equation: 



16=2(u+3)-7

We move all terms to the left:

16-(2(u+3)-7)=0



We calculate terms in parentheses: -(2(u+3)-7), so:

2(u+3)-7

We multiply parentheses

2u+6-7

We add all the numbers together, and all the variables

2u-1

Back to the equation:

-(2u-1)



We get rid of parentheses

-2u+1+16=0

We add all the numbers together, and all the variables

-2u+17=0

We move all terms containing u to the left, all other terms to the right

-2u=-17

u=-17/-2

u=8+1/2

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