6(x-4)=3(2-3x)+15

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Solution for 6(x-4)=3(2-3x)+15 equation: 



6(x-4)=3(2-3x)+15

We move all terms to the left:

6(x-4)-(3(2-3x)+15)=0

We add all the numbers together, and all the variables

6(x-4)-(3(-3x+2)+15)=0

We multiply parentheses

6x-(3(-3x+2)+15)-24=0



We calculate terms in parentheses: -(3(-3x+2)+15), so:

3(-3x+2)+15

We multiply parentheses

-9x+6+15

We add all the numbers together, and all the variables

-9x+21

Back to the equation:

-(-9x+21)



We get rid of parentheses

6x+9x-21-24=0

We add all the numbers together, and all the variables

15x-45=0

We move all terms containing x to the left, all other terms to the right

15x=45

x=45/15

x=3

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