6(x-4)/4=3(x+4)/10

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Solution for 6(x-4)/4=3(x+4)/10 equation:



6(x-4)/4=3(x+4)/10
We move all terms to the left:
6(x-4)/4-(3(x+4)/10)=0
We calculate fractions
6x/()+(-(3(x+4)*4)/()=0
We calculate terms in parentheses: +(-(3(x+4)*4)/(), so:
-(3(x+4)*4)/(
We multiply all the terms by the denominator
-(3(x+4)*4)
We calculate terms in parentheses: -(3(x+4)*4), so:
3(x+4)*4
We multiply parentheses
12x+48
Back to the equation:
-(12x+48)
We get rid of parentheses
-12x-48
Back to the equation:
+(-12x-48)
We get rid of parentheses
6x/()-12x-48=0
We multiply all the terms by the denominator
6x-12x*()-48*()=0
We add all the numbers together, and all the variables
6x-12x*()=0

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